JsonObject::remove()
Description
Removes the element at the specified key.
Signatures
void remove(const char* key);
void remove(const String& key);
void remove(const std::string& key);
void remove(const __FlashStringHelper* key);
Arguments
key
: the key to remove from the object.
Example
JsonObject& object = jsonBuffer.createObject();
object["A"] = 1;
object["B"] = 2;
object["C"] = 3;
object.remove("B");
object.printTo(Serial);
will print the following string to the serial output:
{"A":1,"C":3}
See also
Causes memory leaks
This function doesn’t free the memory allocated to the element in the
JsonBuffer
.This is a conscious design decision made to keep the
JsonBuffer
fast and small, which is a fundamental principle of the library.As a consequence, you cannot remove and add elements in a loop, otherwise the
JsonBuffer
will overflow.Don’t try to keep the state of your application in a
JsonObject
, instead use custom structures.